(4x+1)^2-8=1

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Solution for (4x+1)^2-8=1 equation: 



(4x+1)^2-8=1

We move all terms to the left:

(4x+1)^2-8-(1)=0

We add all the numbers together, and all the variables

(4x+1)^2-9=0

We move all terms containing x to the left, all other terms to the right

(4x+1)^2=9

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